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Pneumatics

Making machines move with compressed air — components and symbols, cylinders, 3/2 and 5/2 valves, pneumatic logic, and pressure–force–area calculations.

Topic 6 booklet — PDF coming soon Open NoPressureSim Data booklet (formulae) Go to self-check

Exam = tested in the written paper most years. Assignment = also used in assignment Task 5 (pneumatic time-delay circuit & safety modification).

Sections:
Concept 1

Pneumatics in engineering Exam

Pneumatics is the use of compressed air to move and control machines. Air is compressed by a compressor, stored in a reservoir, and when a valve is operated the compressed air pushes a piston inside a cylinder — producing a force or movement.

SectorExamples
Industrialproduction-line cylinders, automatic tools, robotic grippers
Transportbus and train brake actuators (compressed-air assisted)
Commercialsliding doors, packaging machines, dental drills
Workshopair-powered nail gun, paint sprayer, impact wrench
AdvantagesDisadvantages
Air is freely available; safe if a leak occurs (no pollution)Compressed air is noisy when released
Cylinders are simple and reliableAir is springy — less precise than hydraulic systems
Safe in damp or flammable areas (no electrical sparks at the cylinder)Forces are limited compared to hydraulics
Speed is easy to control with restrictorsA compressor uses electrical energy and creates wasted heat

Safety — pneumatic safety rules

  • Always wear safety goggles when working with compressed air.
  • Never point a hose or air jet at yourself or another person.
  • Check all hose connections are secure before turning on the supply.
  • Use the correct working pressure (about 4–6 bar at school level).
  • Do not look directly down a cylinder when air is supplied.
  • When finished, isolate the air supply and let the pressure release safely.
Concept 2

Pneumatic components Exam

Every pneumatic system starts with the same three parts: the compressor compresses air to a higher pressure, the reservoir stores it ready to be used, and the regulator sets a safe, constant working pressure.

Learn the data-booklet symbol for each component — engineers use standard symbols so a circuit means the same thing to everyone.

Compressor
Compressor
Compresses air to a higher pressure.
Reservoir
Reservoir
Stores compressed air ready to be used.
Regulator
Regulator
Sets a safe, constant working pressure.
Single-acting cylinder
Single-acting cylinder
Extends with air; returns by spring.
Double-acting cylinder
Double-acting cylinder
Air powers the piston both ways.
3/2 valve (push-button, spring return)
3/2 valve
3 ports, 2 positions — controls a single-acting cylinder.
5/2 valve (push-button, spring return)
5/2 valve
5 ports, 2 positions — controls a double-acting cylinder.
Unidirectional restrictor
Unidirectional restrictor
Restricts flow one way only — speed control & time delays.
Shuttle valve
Shuttle valve
Passes air from either of two inputs (OR logic).

Match the component

Choose the component that does each job, then check. (Task 1 in your booklet.)

Concept 3

Cylinders Exam

In a single-acting cylinder, compressed air pushes the piston out (the outstroke); a spring pushes it back (the instroke). In a double-acting cylinder, air can be supplied to either side of the piston — powered outstroke and powered instroke.

Single-acting (SAC)Double-acting (DAC)
Outstrokecompressed aircompressed air
Instrokespringcompressed air (other side)
Controlled by3/2 valve5/2 valve
Examplessimple clamp, conveyor ejectorpneumatic door, two-way clamp, robot gripper
Required terminology — markers expect these exact words. The 3/2 valve actuates · the 5/2 valve changes state · the piston outstrokes (extends) or instrokes (retracts). Never write "the valve goes" or "the piston moves out".
Marked practice question — describe the operation (model answer)

Q. A push-button 3/2 valve controls a single-acting cylinder. Using the correct terminology, describe what happens when the button is pressed and then released. 2 marks

Model answer: When the button is pressed the 3/2 valve actuates, so compressed air is supplied to the cylinder and the piston outstrokes (1). When the button is released the 3/2 valve returns and the air is exhausted, so the spring makes the piston instroke (1).

▶ Simulate it 1

Single-acting cylinder + 3/2 valve

  1. Build: Air Supply → 3/2 button valve → single-acting cylinder. Switch to Symbol Mode and compare with the data-booklet symbols.
  2. Predict: what happens when you press the button? When you release it? Run and check — which part makes the piston return?
  3. Change one thing: switch the 3/2 valve from normally-closed (NC) to normally-open (NO). Predict, then run. What is different, and why?
▶ Simulate it 2

Double-acting cylinder + 5/2 valve

  1. Build: Air Supply → 5/2 pilot valve → double-acting cylinder.
  2. Predict which way the piston moves in each valve state, then run and switch the valve. Why does a double-acting cylinder need a 5/2 and not a 3/2?
  3. Describe the action: "the 5/2 valve changes state, the piston outstrokes / instrokes." Export the image (press I) for your notes.
Concept 4

Valves, time delays and pneumatic logic ExamAssignment

A valve must be actuated (switched) to change which ports are connected. A 3/2 valve (3 ports, 2 positions) controls a single-acting cylinder; a 5/2 valve (5 ports, 2 positions) moves the air supply from one side of a double-acting cylinder's piston to the other.

ValvePortsPort functionsControls
3/23 ports, 2 positions1 = air supply in · 2 = to cylinder · 3 = exhaustsingle-acting cylinder
5/25 ports, 2 positions1 = air supply in · 2 & 4 = to each side of the cylinder · 3 & 5 = exhaustsdouble-acting cylinder

Ways of actuating a valve

MethodHow it worksTypical use
Manual — push-button, lever, pedala person operates the valve directlyoperator start/stop control
Mechanical — roller or plungera moving part of the machine trips the valvedetecting the end of a piston stroke
Pilot-aira small air signal on a control port moves the valvelinking valves for automatic sequences
Solenoid (electrical)an electromagnetic coil moves the valveconnecting pneumatics to a microcontroller
Diaphragmair pressure on a flexible diaphragm switches the valvepressure sensing
The solenoid valve is the key link between electronics and pneumatics: a microcontroller output energises the solenoid, the solenoid actuates the valve, and the valve operates the cylinder.

Restrictors and the time delay

A restrictor slows the air flow in both directions. A unidirectional restrictor restricts one direction only — air passes freely the other way through a non-return valve — so an engineer can slow the outstroke without slowing the instroke. Combine a unidirectional restrictor with a small reservoir and you get a time delay: air slowly fills the reservoir through the restricted side, and once the pressure reaches the switching value it operates a pilot-air valve. The greater the restriction, the longer the delay.

Pneumatic logic — AND and OR

Logic functionHow it is builtMeaning
ANDtwo 3/2 valves in seriesoutput only when both valves are operated — used for two-hand safety controls
ORa shuttle valveoutput when either input is operated — start a cylinder from two different buttons
Link to Topic 4: pneumatic AND (two valves in series) and OR (a shuttle valve) do the same job as the AND and OR logic gates in Logic & Programmable Control — the same logic can be built from air or from electronics.
▶ Simulate it 3

Speed control with a restrictor

  1. Add a restrictor between the 5/2 valve and the double-acting cylinder. Set restriction to 0%, then run.
  2. Predict, then test at 50%, then 90%. Record the outstroke speed (fast / medium / slow) at each setting.
  3. Change one thing: use a unidirectional restrictor so only the outstroke is slowed. How could an engineer get a slow outstroke but a fast instroke?
▶ Simulate it 4

Time delay with a reservoir

  1. Build a pilot circuit where a restrictor feeds a reservoir that pilots a valve to fire the cylinder.
  2. Predict: with a high restriction, does the cylinder fire sooner or later? Run and time it.
  3. Change one thing: lower the restriction %. Predict the new delay, then test. State the rule linking restriction to delay.
▶ Simulate it 5 & 6

OR logic (shuttle valve) and AND logic (two-hand safety)

  1. OR: build two 3/2 button valves → shuttle valve → cylinder. Predict: will the cylinder fire from button A only? B only? Both? Test each. Why is this called OR?
  2. AND: build two 3/2 valves in series → cylinder. Does it fire with one button? With both? Why are two valves in series an AND?
  3. Link the AND circuit to a two-hand press, where both hands must press for the machine to operate — a safety control.

Choose the valve or circuit

Pick the right component or arrangement for each job, then check.

Concept 5

Pressure, force and area Exam

The output force from a cylinder depends on the air pressure and the piston area. Pistons are circular, so when a question gives the diameter, find the area first with A = πd²/4.

⚠ Units — read this first

  • Work in newtons (N) and square millimetres (mm²) — this gives pressure in N mm⁻² (the same as N/mm²). Keep the diameter in mm and there is no need to convert to metres.
  • 1 N mm⁻² = 1 000 000 Pa. If a question gives pressure in Pa, convert before mixing units — mixing Pa with mm² is the most common mistake.
Pressure
P = FA
force ÷ area · N mm⁻², N, mm²
Area of a circular piston
A = πd24
diameter in mm gives area in mm²
Worked example — force from area (substitute & solve)
Substitute & solve
A pneumatic cylinder has a piston area of 2000 mm² and a working pressure of 0.6 N mm⁻². Calculate the outstroke force.
P=F ÷ A
0.6=F ÷ 2000numbers in first
F=0.6 × 2000now rearrange
F=1200 N
Worked example — force from diameter (two steps)
Two-step — area first
A double-acting cylinder has a piston of diameter 50 mm. The working pressure is 0.5 N mm⁻². Calculate the outstroke force.

Step 1 — find the area:

A=πd2 ÷ 4
A=π × 502 ÷ 4
A=1963 mm²

Step 2 — find the force:

F=P × A
F=0.5 × 1963
F=982 N
Worked example — rearrange (find the area needed)
Rearrange — numbers in first
A force of 1500 N is needed at a pressure of 0.5 N mm⁻². Calculate the area of the piston needed.
P=F ÷ A
0.5=1500 ÷ Anumbers in first
A=1500 ÷ 0.5now rearrange
A=3000 mm²
Outstroke vs instroke. On a double-acting cylinder the instroke force is smaller than the outstroke force at the same pressure — the piston rod takes up some of the area on the instroke side, so the air acts on a smaller (effective) area.

💨 Cylinder force calculator — live

Drag the piston diameter and the working pressure. The calculator shows both steps: area first (A = πd²/4), then force (F = P × A).

step 1 — area (mm²)
step 2 — outstroke force (N)

Challenge: a machine needs an outstroke force between 1400 N and 1430 N. Find a diameter-and-pressure combination that delivers it.

Concept 6

Circuits, design & investigate Assignment

A pneumatic circuit diagram shows how the components connect, drawn with the standard data-booklet symbols. Engineers draw the circuit before building — it checks the design works and lets anyone else read and build it.

The three reference circuits

CircuitBuilt fromWhat it does
1 — Basic single-actingsupply → 3/2 push-button valve → SACpress = outstroke; release = spring instroke
2 — Basic double-actingsupply → 5/2 valve → both ports of a DACvalve state chooses outstroke or instroke
3 — Speed controlcircuit 2 + a unidirectional restrictor on each sideindependent control of extension and retraction speed

Build each one — on the school kit (safety check before applying air!) or in NoPressureSim — draw the diagram first, predict the behaviour, then test.

▶ Simulate it 7 — extension

Automatic sequence with a limit switch

  1. Build a double-acting cylinder controlled by a 5/2 pilot valve. Add a roller limit valve at the end of the stroke, labelled "A+" to match the cylinder "A".
  2. Predict: what does the cylinder do when it reaches full extension? Run it — you have built a semi-automatic sequence: the machine detects its own position.
  3. Link this to solenoid control: a microcontroller output can energise a solenoid, which actuates the valve.

Design briefs — there is more than one good answer

◆ Design brief A

Automatic sliding door

  1. An automatic sliding door must open and close under air, closing slowly for safety. Design and build the circuit, then run it.
Hint
Double-acting cylinder + 5/2 valve + a unidirectional restrictor on the closing side.
◆ Design brief B

Two-hand press, two stations

  1. A press must operate only when the operator uses both hands, and must be startable from either of two work stations. Design and build the circuit.
Hint
Combine AND (two valves in series for two-hand safety) with OR (a shuttle valve for the two stations).
◆ Design brief C

Automatic retract

  1. Make the cylinder retract automatically when it reaches the end of its stroke. Design and build the circuit.
Hint
Use a roller limit valve labelled "A+" to detect full extension.
Assignment link. Save your circuit (Save .json) and export the image (press I) — write one sentence on the job of each component and test the circuit against the brief. This is exactly the evidence Booklet 8 — Assignment Skills asks for in Task 5: a time-delay circuit (restrictor + reservoir between the 3/2 and 5/2), a unidirectional restrictor slowing the outstroke on the exhaust, two 3/2 valves piped to the 5/2, and a justified safety modification.

Common mistakes — watch out for these in the exam

  • Mixing units — a pressure in Pa with an area in mm². Work in N and mm² (N mm⁻²), or convert everything; never mix the two.
  • Forgetting to find the piston area first when only the diameter is given (A = πd²/4).
  • Writing "the valve goes" or "the piston moves" instead of actuates, changes state, instrokes, outstrokes.
  • Confusing the logic — AND is two valves in series; OR is a shuttle valve.
  • Choosing the wrong valve — a 3/2 controls a single-acting cylinder, a 5/2 controls a double-acting cylinder.
Booklet check

Check your booklet work

Try each task in your booklet first, then open the matching answer. Round calculated answers sensibly and always show working and units.

Try This — final answers

Try This — Pressure and force §5
  1. F = P × A = 0.6 × 1000 = 600 N
  2. A = F ÷ P = 1500 ÷ 0.5 = 3000 mm²
  3. P = F ÷ A = 1000 ÷ 2500 = 0.4 N mm⁻²
Try This — Piston area and force §6
  1. A = πd²/4 = π × 40² ÷ 4 = 1257 mm²
  2. A = π × 25² ÷ 4 = 491 mm²; F = 0.4 × 491 = 196 N
  3. A = π × 60² ÷ 4 = 2827 mm²; F = 0.5 × 2827 = 1414 N

Section practice — final answers

Practice — Pneumatics in Engineering §1
  1. Using compressed air to move and control machines.
  2. Any two: production-line cylinders, automatic tools, robotic grippers.
  3. Any one: sliding doors, packaging machines, dental drills.
  4. Air is clean/safe if it leaks; simple and reliable; safe near damp or flammable areas.
  5. Noisy when released; springy (less precise); limited force; compressor wastes energy.
  6. Any two safety rules, e.g. wear goggles; never point a hose at anyone; check connections.
  7. No electrical spark at the cylinder, so no ignition risk in flammable/damp areas.
  8. About 4–6 bar at school level.
  9. Liquids are (almost) incompressible, so hydraulics transmit larger forces without "give".
  10. Any two: air-powered nail gun, paint sprayer, impact wrench, air drill.
Practice — Pneumatic Components §2
  1. Compresses air to supply the system.
  2. Stores compressed air at the working pressure.
  3. Sets a safe, constant working pressure.
  4. See the symbol grid above (reservoir).
  5. See the symbol grid above (regulator).
  6. Regulator.
  7. Restrictor.
  8. The reservoir stores air and smooths the supply, so the system keeps working while the compressor refills.
  9. Passes air from either of two inputs to one output (OR logic).
  10. Standard symbols are understood by all engineers and make circuits quick to read and build.
Practice — Cylinders §3
  1. Air pushes the piston out (outstroke); a spring returns it (instroke).
  2. Air drives the piston both ways — powered outstroke and powered instroke.
  3. Double-acting cylinder.
  4. Single-acting cylinder.
  5. See the symbol grid above (single-acting).
  6. See the symbol grid above (double-acting).
  7. It uses one air connection and a spring return, so it is simpler and needs less.
  8. Any powered push-and-pull task, e.g. a robot gripper or a two-way clamp.
  9. Any push-and-return task, e.g. a stamping/clamping tool with a spring return.
  10. A gripper must be powered both to close and to open (hold and release), which needs a double-acting cylinder.
Practice — Valves §4
  1. Controls a single-acting cylinder (air on / exhaust).
  2. Controls a double-acting cylinder (air to each side in turn).
  3. 3 ports, 2 positions.
  4. 5 ports, 2 positions.
  5. It restricts air flow one way only, slowing the piston in that direction to control speed.
  6. Two inputs, one output; passes air from either input (OR logic).
  7. A small pilot-air signal on the control port moves the spool, switching the valve without a hand — used to link valves for automatic sequences.
  8. A restrictor slowly fills a reservoir; when the pressure is high enough it pilots the next valve — more restriction gives a longer delay.
  9. 5/2 valve.
  10. A shuttle valve — it passes air from either button to the cylinder (OR).
Practice — Pneumatic Calculations §5–6
  1. P = F ÷ A.
  2. A = πd² ÷ 4.
  3. F = 0.6 × 2000 = 1200 N
  4. A = π × 60² ÷ 4 = 2827 mm²; F = 0.5 × 2827 = 1414 N
  5. A = π × 80² ÷ 4 = 5027 mm²; F = 0.4 × 5027 = 2011 N
  6. A = F ÷ P = 2000 ÷ 0.5 = 4000 mm²
  7. P = F ÷ A = 900 ÷ 1500 = 0.6 N mm⁻²
  8. The rod takes up part of the piston area on the instroke, so the effective area is smaller; F = P × A, so a smaller area gives a smaller force at the same pressure.
  9. A = π × 100² ÷ 4 = 7854 mm²
  10. A = π × 35² ÷ 4 = 962 mm²; F = 0.6 × 962 = 577 N
Practice — Pneumatic Circuits §7
  1. 5/2 valve.
  2. 3/2 valve.
  3. Fit a unidirectional restrictor on the outstroke side, so air is restricted only as the piston extends.
  4. Supply → 3/2 push-button valve → single-acting cylinder (see reference circuit 1).
  5. Supply → 5/2 valve → both ports of a double-acting cylinder (see reference circuit 2).
  6. A shuttle valve feeds the cylinder from either button, so either one starts it (OR).
  7. To make sure connections are secure and no hose can whip or leak — for safety.
  8. Unidirectional restrictor on the outstroke side (slow out); air flows freely on the instroke (fast in).
  9. It checks the design works and lets others read/build it using standard symbols.
  10. The button pilots the 5/2 valve to change state, sending air to extend the cylinder automatically.
Check yourself

Check yourself

Mixed multiple choice

One question from every part of the topic. Choose an answer for each, then mark them.

Rate your confidence — the booklet's success criteria

These are the success criteria from your booklet. Red = not yet, Amber = getting there, Green = confident. Saved on this device.

Ready for exam questions? Open the Past Paper Finder and look for the pneumatics questions.

Sources & credits: The Topic 6 booklet © R Stewart, 2026. NoPressureSim is a free simulator by R Stewart. The Past Paper Finder is compiled by Mr McDonald, 2024; past-paper questions © Qualifications Scotland (SQA). The N4/N5 data booklet is reproduced for educational use, © Qualifications Scotland (SQA).